Ferestrau-Oituz
Ferestrau-Oituz is a city in Romania with a population of about 1,036.
Oituz is a commune in Bacău County, Western Moldavia, Romania. It is composed of six villages: Călcâi (Zöldlonka), Ferestrău-Oituz (Fűrészfalva), Hârja (Herzsa), Marginea, Oituz, and Poiana Sărată (Sósmező).
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About Ferestrau-Oituz
| Country | Romania |
| Continent | Europe |
| Explore | 04 |
| Population | 1,036 |
| Local currency | RON |
| Coordinates | 46.2025, 26.5763 |
| Time zone | Europe/Bucharest |
🧭 Facts & curiosities
| Settlement type | Small town |
| Distance to the capital | 200 km · Bucharest |
| Population (Romania) | #4174 most populated in Romania |
| Where on Earth | 46°12′9″N · 26°34′35″E |
| Hemisphere | N · E |
| Distance to the equator | 5,143 km |
| Distance to the North Pole | 4,876 km |
| Did you know | More populous than 97% of all places |
| Same latitude as | Astrakhan (Russia) |
| Antipode (other side of Earth) | -46.20, -153.42 |
✈️ Distance to major cities
| Moscow | 1,310 km |
| Paris | 1,834 km |
| Cairo | 1,841 km |
| London | 2,028 km |
| Dubai | 3,453 km |
| Beijing | 6,929 km |